JS.BASE.CONSTRUCTOR.SUPER
Require 'super()' calls in constructors
Constructors of derived classes must call super()
.
Constructors of non derived classes must not call super()
.
If this is not observed, the JavaScript engine will raise a runtime error.
This rule checks whether or not there is a valid super()
call.
Rule Details
This rule is aimed to flag invalid/missing super()
calls.
Examples of incorrect code for this rule:
Copy
/*eslint constructor-super: "error"*/
/*eslint-env es6*/
class A {
constructor() {
super(); // This is a SyntaxError.
}
}
class A extends B {
constructor() { } // Would throw a ReferenceError.
}
// Classes which inherits from a non constructor are always problems.
class A extends null {
constructor() {
super(); // Would throw a TypeError.
}
}
class A extends null {
constructor() { } // Would throw a ReferenceError.
}
Examples of correct code for this rule:
Copy
/*eslint constructor-super: "error"*/
/*eslint-env es6*/
class A {
constructor() { }
}
class A extends B {
constructor() {
super();
}
}
When Not To Use It
If you don't want to be notified about invalid/missing super()
callings in constructors, you can safely disable this rule.