STRONG.TYPE.ASSIGN.ZERO
Assignment of zero to strong type variable
The STRONG.TYPE family of checkers detects situations in which programmer-enforced strong typing (type-defined abstract types) is broken or ignored, allowing the underlying ANSI type semantics to dominate.
The STRONG.TYPE.ASSIGN.ZERO checker finds assignments of zero to a variable of a strong type. In this rule, zero is defined as any zero constant that has not been cast to a strong type. For example, the checker considers the following to be zero:
- 0L
- (int)0
The checker considers the following examples not to be zero:
- (SPEED)0
- (SPEED*)0
Vulnerability and risk
A compiler following the ANSI standard won't report a warning for this sort of issue, as it checks only the underlying types, not the surface, or programmer-defined, types. As a result, it's possible that a logic error can occur.
Vulnerable code example
typedef int Weight;
int main() {
Weight ElephantW;
ElephantW = 0;
return 0;
}Klocwork flags line 5, in which zero is assigned to strong type ElephantW.
